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【大智慧】寶石起漲主圖指標公式

2015.11.08 22:08

MA5:MA(C,5);
MA10 :MA(close,10);
MA60 : MA(close,60);
GJTJ1:=100*(C-LLV(L,5))/(HHV(C,5)-LLV(L,5));
GJTJ2:=100*(C-LLV(L,10))/(HHV(C,10)-LLV(L,10));
GJTJ3:=100*(C-LLV(L,20))/(HHV(C,20)-LLV(L,20));
GJTJ4:=100*(C-LLV(L,30))/(HHV(C,30)-LLV(L,30));
baijin1:=BARSLAST(CROSS(30,GJTJ1))<2 AND
BARSLAST(CROSS(GJTJ1,50))<2;
baijin2:=BARSLAST(CROSS(GJTJ4,GJTJ1))<2 AND GJTJ1>GJTJ4;
baijin3:=GJTJ1>60 AND GJTJ4>70;
drawtext(baijin1 AND baijin2 AND baijin3,l-0.02,’l瑪瑙’);
huangjin1:=BARSLAST(CROSS(50,GJTJ1))<3 AND
BARSLAST(CROSS(GJTJ1,50))<3;
huangjin2:=BARSLAST(CROSS(GJTJ4,GJTJ1))<2 AND GJTJ1>GJTJ4;
DRAWTEXT(huangjin1 AND huangjin2,l-0.03,’鉆石’);
XG:=BARSLAST(CROSS(GJTJ4,GJTJ1))<5 AND GJTJ1>GJTJ4;
drawtext(COUNT(XG,3)=1 AND XG and
c>ma(c,20),l-0.02,’啟動’),colorred;
zhencang1:=BARSLAST(CROSS(GJTJ4,GJTJ1))>3 AND
BARSLAST(CROSS(GJTJ1,GJTJ4))<3;
zhencang2:=BARSLAST(CROSS(GJTJ4,GJTJ2));
zhencang3:=GJTJ3 zhencang4:=BARSLAST(CROSS(GJTJ4,GJTJ3))>3 AND
BARSLAST(CROSS(GJTJ1,GJTJ4))<3;
zhencang5:=GJTJ2 GJTJ1=100;
zcB1:=zhencang1>0 AND REF(zhencang1,1)=0 AND
REF(zhencang1,2)>0;
drawtext(zhencang1 AND zhencang2 AND zhencang3 AND zhencang4
AND zhencang5,l-0.05,’震倉啟點’);
Aa:=BARSLAST(CROSS(97,GJTJ1))<=1 AND
BARSLAST(CROSS(GJTJ1,85))<=1;
Bb:=BARSLAST(CROSS(97,GJTJ2))<=1 AND
BARSLAST(CROSS(GJTJ2,85))<=1;
Aa1:=Aa AND Bb;
AAa:=BARSLAST(CROSS(97,GJTJ1))<=2 AND
BARSLAST(CROSS(GJTJ1,85))<=1;
BAa:=BARSLAST(CROSS(97,GJTJ2))<=2 AND
BARSLAST(CROSS(GJTJ2,85))<=1;
Aa2:=AA AND Bb ;
AAAa:=BARSLAST(CROSS(97,GJTJ1))<=3 AND
BARSLAST(CROSS(GJTJ1,85))<=1;
BAAa:=BARSLAST(CROSS(97,GJTJ2))<=3 AND
BARSLAST(CROSS(GJTJ2,85))<=1;
Aa3:=AAAa AND BAAa ;
Bb1:=REF(Aa1,1);
Bb2:=REF(Aa2,1);
Bb3:=REF(Aa3,1);
Dd1:=GJTJ1=100 AND GJTJ2=100 AND Aa1 ;
Dd2:=GJTJ1=100 AND GJTJ2=100 AND Aa2 ;
Dd3:=GJTJ1=100 AND GJTJ2=100 AND Aa3 ;
drawtext(Dd1 OR Dd2 OR Dd3,l-0.02,’短線追漲’);
Aw:=BARSLAST(CROSS(95,GJTJ1))<=2;
Bw:=BARSLAST(CROSS(95,GJTJ2))<=2;
Ew:= GJTJ4 Fw:=GJTJ2>50 AND GJTJ3>50;
Gw:=GJTJ1=100 AND GJTJ2=100;
TXw:=COUNT(Gw,2)=1;
drawtext(Aw AND Bw AND Ew AND Fw AND TXw,l-0.03,’起漲’);
Aq:=GJTJ3=100;
Bq:=GJTJ4<90;
drawtext(COUNT(Aq,2) = 2 AND Bq,l-0.02,’波啟前兆’);

 

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